Question
Write $\cot^{-1}$ $\left(\frac{1}{\sqrt{x^{2}-1}}\right), x>1$ in the simplest form.

Answer

Let $x = \sec  \theta$,
then $\sqrt{x^{2}-1}=\sqrt{\sec ^{2} \theta-1}$ = tan $\theta$
Therefore, $\cot ^{-1} \frac{1}{\sqrt{x^{2}-1}}=\cot ^{-1}(\cot \theta)=\theta=\sec ^{-1} x$ , is the simplest form.

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