Question
Write electrode reactions and overall cell reaction for Daniel cell you learnt in standard XI.
Oxidation at $Zn$ anode :
$
Zn _{( s )} \rightarrow Zn _{( qq )}^{2+}+2 e ^{-} (Oxidation half reaction)
$
Reduction at Cu cathode :
$
\frac{ Cu _{( aq )}^{2+}+2 e ^{-} \rightarrow Cu _{( s )} \text {( Reduction half reaction ) }}{ Zn _{( s )}+{(1 M )}{ Cu _{( aq )}^{2+}} \rightarrow {(1 M )}{ Zn _{( aq )}^{2+}}+ Cu _{( s )}}
$
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