Write note on oxides and oxoanions of 3d transition metals.

Question

Write note on oxides and oxoanions of $3d$ transition metals.

✓

Answer

$\rightarrow$ The ability of oxygen to stabilize the high oxidation states of metal than fluorine is higher because it forms a multiple bonds with a metal.
$\rightarrow$ The metal oxide in lower oxidation state is basic while in higher oxidation state are acidic.
$\rightarrow$ The metal oxides having metals in intermediate oxidation states are amphoteric.
e.g.

Acidic oxide	Basic oxide	Amphoteric oxide
$\ce{Mn_2O_7}$	$\ce{MnO}$	$\ce{Mn_3O_4, Mn_2O_3, MnO_2}$
	$CrO$	$\ce{Cr_2 O_3}$

Oxides of $3d$ Metals

Oxidati on NUmber

$3$

$4$

$5$

$6$

$7$

$8$

$9$

$10$

$11$

$12$

$+7$

$Mn _2 O _7$

$+6$

$CrO _3$

$+5$

$V _2 O _5$

$+4$

$TiO _2$

$V _2 O _4$

$CrO _2$

$MnO _2$

$+3$

$\ce{Sc_2O_3}$

$Ti _2 O _3$

$V _2 O _3$

$Cr _2 O _3$

$ Mn _2 O _3$
$Mn _3 O _4^*$

$MnO$

$ Fe _2 O _3$
$Fe _3 O _4^*$

$CoO$

$Co _3 O _4{ }^*$

$+2$

$TiO$

$VO$

$(CrO)$

$MnO$

$FeO$

$CoO$

$NiO$

$CuO$

$ZnO$

$+1$

$Cu _2 O$

* mixed oxides
$\rightarrow$ In the covalent oxide $\ce{Mn_2O_7}$, each Mn is tetrahedrally surrounded by $O$ 's including a $\ce{Mn - O - Mn}$ bridge. The tetrahedral $\left[ \ce{MO _4}\right]^{ n -}$ ions are known for $\ce{V ^{ V }, Cr ^{ VI }, Mn ^{ V }, Mn ^{ VI }}$ and $\ce{Mn ^{ VII }}$.

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