Question
Write tha value of $\int\sec\text{x}(\sec\text{x}+\tan\text{x})\text{dx}$

Answer

$\int\sec\text{x}(\sec\text{x}+\tan\text{x})\text{dx}$
$=\int(\sec^2\text{x}+\sec\text{x}\tan\text{x})\text{dx}$
$=\tan\text{x}+\sec\text{x}+\text{C}$

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