Question
Write the complement angle of: $\frac{1}{6}$ of $90^{\circ}$

Answer

Complement angle of $\frac{1}{6}$ of $90^{\circ}$
$
=90^{\circ}-\left(\frac{1}{6} \times 90^{\circ}\right)
$
= 90° - 15°
= 75°

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