Question
Write the complement of an angle of measure $x^\circ .$
✓
Answer
We have to write the complement of an angle which measures $x^{\circ}$.
Let the other angle be $y^{\circ}$.
We know that the sum of the complementary angles be $90^{\circ}$.
Therefore, $x^{\circ}+y^{\circ}=90^{\circ} y^{\circ}=(90-x)^{\circ}$
Let the other angle be $y^{\circ}$.
We know that the sum of the complementary angles be $90^{\circ}$.
Therefore, $x^{\circ}+y^{\circ}=90^{\circ} y^{\circ}=(90-x)^{\circ}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the following product:
$\text{a}^3 - 2\sqrt{2}\text{b}^3$
→$\text{a}^3 - 2\sqrt{2}\text{b}^3$
The mean weight of a class of $36$ students is $41kg$. If one of the students leaves the class then the mean is decreased by $200g.$ Find the weight of the student who left.
→Factorise:
$x-8 x y^3$
→$x-8 x y^3$
Factorise: $\text{x}^2-2\sqrt{3}\text{x}-24$
→Express $0.35 \overline{7}$ in the form $\frac{p}{q}$, where $p$ and $q$ are integers and $q \neq 0$.
→Simplify the following expression:$(\sqrt{5}-2)(\sqrt{3}-\sqrt{5})$
→Look at the bar graph given below.
If $\text{x}=\text{a}^{\text{m}+\text{n}},\ \text{y}=\text{a}^{\text{n}+\text{l}}$ and $\text{z}=\text{a}^{\text{l}+\text{m}},$ prove that $\text{x}^\text{m}\text{y}^\text{n}\text{z}^\text{l}=\text{x}^\text{n}\text{y}^\text{l}\text{z}^\text{m}.$
→Factorise:
$x^2-(a+b) x+a b$
→$x^2-(a+b) x+a b$
Verify $x = - \frac{1}{2}$ are zeroes of the polynomial $p\left( x \right) = 2x + 1$
→