MCQ
Write the correct answer in the following: $ABCD$ is a cyclic quadrilateral such that $AB$ is a diameter of the circle circumscribing it and $\angle\text{ADC}=140^\circ,$ then $\angle\text{BAC}$ is equal to:
- A$80^\circ .$
- ✓$50^\circ .$
- C$40^\circ .$
- D$30^\circ .$


