MCQ
Write the correct answer in the following: If $\text{p}\text{(x)}=\text{x}^2-2\sqrt{2\text{x}}+1,$ then is $\text{p}(2\sqrt{2})$ equal to.
  • A
    $0$
  • $1$
  • C
    $4\sqrt{2}$
  • D
    $8\sqrt{2}+1$

Answer

Correct option: B.
$1$
We have,
$\text{p}\text{(x)}=\text{x}^2-2\sqrt{2}\text{x}+1$
$\text{p}(2\sqrt{2})=(2\sqrt{2})^2-2\sqrt{2}(2\sqrt{2})+1$
$= 8 - 8 + 1$
$= 1$

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