Answer

  1. 70°.
    Solution:
    In $\triangle\text{ADB},$ we have
    $\angle\text{A}+\angle\text{B}+\angle\text{D}=180^\circ$ [Angle sum property of a triangle]
    $\Rightarrow60^\circ+50^\circ+\angle\text{D}=180^\circ$
    $\Rightarrow\angle\text{D}=180^\circ-110^\circ=70^\circ$
    i.e., $\angle\text{ABD}=70^\circ$
    Now, $\angle\text{ACB}=\angle\text{ADB}=70^\circ$
    [$\because$ Angles in the same segment of a circle are equal]
    Hence, (c) is the correct answer.

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