70°. Solution: In $\triangle\text{ADB},$ we have $\angle\text{A}+\angle\text{B}+\angle\text{D}=180^\circ$ [Angle sum property of a triangle] $\Rightarrow60^\circ+50^\circ+\angle\text{D}=180^\circ$ $\Rightarrow\angle\text{D}=180^\circ-110^\circ=70^\circ$ i.e., $\angle\text{ABD}=70^\circ$ Now, $\angle\text{ACB}=\angle\text{ADB}=70^\circ$ [$\because$ Angles in the same segment of a circle are equal] Hence, (c) is the correct answer.
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