MCQ
Write the correct answer in the following: $\sqrt{2}$ is a polynomial of degree.
- A$2$
- ✓$0$
- C$1$
- D$\frac{1}{2}$
$\sqrt{2}$ is a constant polynomial. The only term here is $\sqrt{2}$ which can be written as $\sqrt{2}\text{x}^\circ.$ So, the exponent of $x$ is zero. Therefore, the degree of the polynomial is $0.$
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