Write the dimensions of a/b in the relation P = frac{{a - {t^2}}}{{bx}} , where P is pressure, x is the distance and t is

Q: Write the dimensions of $a/b$ in the relation $P = \frac{{a - {t^2}}}{{bx}}$ , where $P$ is pressure, $x$ is the distance and $t$ is the time

b $P=\frac{a-t^{2}}{b x}$ $P=\left[M L^{-1} T^{-2}\right]$ $a$ will have same unit as $t^{2} .$ So, $a=\left[T^{2}\right]$ $b=\left[\frac{a-t^{2}}{p x}\right]=\frac{\left[T^{2}\right]}{\left[M L^{-1} T^{-2} L\right]}=\left[M^{-1} L^{0} T^{4}\right]$ $\frac{a}{b}=\frac{\left[T^{2}\right]}{\left[M^{-1} L^{0} T^{4}\right]}=\left[M L^{0} T^{-2}\right]$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

Write the dimensions of $a/b$ in the relation $P = \frac{{a - {t^2}}}{{bx}}$ , where $P$ is pressure, $x$ is the distance and $t$ is the time

A${M^{ - 1}}{L^0}{T^{ - 2}}$
B${M^1}{L^0}{T^{ - 2}}$
C${M^1}{L^0}{T^{ 2}}$
D${M^1}{L^1}{T^{ - 2}}$

Medium

STD 11 Science
JEE
STD 11 - 1. units,dimensions and measurement
Physics

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