Write the equation of the plane whose intercepts on the coordinat… - Vidyadip

Question

Write the equation of the plane whose intercepts on the coordinate axes are 2, -3 and 4

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Answer

Given, intercepts on the coordinate axes are 2, -3 and 4
We know that,
The equation of a plane whose intercept onb the coordinate axes are a, b and c
$\frac{\text{x}}{\text{a}}+\frac{\text{y}}{\text{b}}+\frac{\text{z}}{\text{c}}=1\ ...(\text{i})$
Here, a = 2, b = -3, c = 4
So,
Equation of required plane is,
$\frac{\text{x}}{2}+\frac{\text{y}}{-3}+\frac{\text{z}}{4}=1$
$\frac{6\text{x}-4\text{y}+3\text{z}}{12}=1$
${6\text{x}-4\text{y}+3\text{z}=}{12}$

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