Question
Write the equation of the unit circle concentric with $x^2 + y^2 - 8x + 4y - 8 = 0$.

Answer

$x^2+y^2-B x+4 y-8=0 x^2-B x+(4)^2-(4)^2+y^2+4 y+(2)^2-(2)^2-8=0(x-4)^2+(y+2)^2-16-4-8=0(x-4)+(y$
$+2)-28=0(x-4)^2+(y+2)^2=28$ $\qquad$ (1) Concentric unit circle to equation (1) is $(x-4)^2+(y+2)^2=1 x^2-B x+$ $y^2+4 y+19=0$

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