Question
Write the first five terms of the sequence whose $n^{th}$ term is $a_n = 2^n$
✓
Answer
Given: $a_n = 2^n$ Putting $n = 1, 2, 3, 4$ and $5,$ we get,
$a_1 = 2^1 = 2$
$a_2 = 2^2 = 4$
$a_3 = 2^3 = 8$
$a_4 = 2^4 = 16$
$a_5 = 2^5 = 32$
Therefore, the first five terms are $2, 4, 8, 16$ and $32.$
$a_1 = 2^1 = 2$
$a_2 = 2^2 = 4$
$a_3 = 2^3 = 8$
$a_4 = 2^4 = 16$
$a_5 = 2^5 = 32$
Therefore, the first five terms are $2, 4, 8, 16$ and $32.$
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