Question
Write the first three terms of $a_{n}=\frac{n-3}{4}$

Answer

Here, $a_{n}=\frac{n-3}{4}$. Thus, $a_{1}=\frac{1-3}{4}=-\frac{1}{2}, a_{2}=-\frac{1}{4}, a_{3}=0$
Therefore the first three terms are $-\frac{1}{2},-\frac{1}{4}$ and 0.

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