Question
Write the first three terms of the sequence whose $n^{\text {th }}$ term is given by $a_n=\frac{n^2}{3^n}$

Answer

$\begin{array}{ll}\text { Here, } & a_n=\frac{n^2}{3^n} \\\therefore & a_1=\frac{1^2}{3^1}=\frac{1}{3} \\\text { } & a_2=\frac{2^2}{3^2}=\frac{4}{9} \\\text { and } & a_3=\frac{3^2}{3^3}=\frac{1}{3}\end{array}$
So, first three terms $=\frac{1}{3}, \frac{4}{9}, \frac{1}{3}$

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