Question
Write the following rational numbers in the standard form: $\frac{299}{-161}$
✓
Answer
The denominator is negative. $\frac{299\times-1}{-161\times-1}$
The $H.C.F.$ of $299$ and $-161$ is $23$.
Dividing the $Nr$ and $Dr$ of $\frac{299}{-161}$ by $23$,
We get: $\frac{299}{-161}=\frac{299\div23}{-161\div23}=\frac{13}{-7}$
The $H.C.F.$ of $299$ and $-161$ is $23$.
Dividing the $Nr$ and $Dr$ of $\frac{299}{-161}$ by $23$,
We get: $\frac{299}{-161}=\frac{299\div23}{-161\div23}=\frac{13}{-7}$
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