Question
Write the following ratios in the simplest form:
Rs. 6.30 : Rs. 16.80
Rs. 6.30 : Rs. 16.80
✓
Answer
The given ratio = Rs. 6.30 : Rs. 16.80
$=\frac{\text{Rs. }6.30}{\text{Rs. }16.80}$
$=\frac{630}{1680}$
To express it in simplest form, we divide the numerator and denominator by the HCF of 630 and 1680.
Now, HCF of 630 and 1680 = 210
$\therefore\frac{630}{1680}=\frac{630\div210}{1680\div210}=\frac{3}{8}$
$\therefore\text{Required ratio}= 3:8$
$=\frac{\text{Rs. }6.30}{\text{Rs. }16.80}$
$=\frac{630}{1680}$
To express it in simplest form, we divide the numerator and denominator by the HCF of 630 and 1680.
Now, HCF of 630 and 1680 = 210
$\therefore\frac{630}{1680}=\frac{630\div210}{1680\div210}=\frac{3}{8}$
$\therefore\text{Required ratio}= 3:8$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The following figure have been split into rectangles. Find the area. (The measures are given in centimeter)
Compare the fractions given below:
$\frac{4}{9},\frac{5}{6}$
→$\frac{4}{9},\frac{5}{6}$
Verify the following:
(-13) × [(-6) + (-19)] = (-13) × (-6) + (-13) × (-19)
(-13) × [(-6) + (-19)] = (-13) × (-6) + (-13) × (-19)
Ramesh bought $2\frac{1}{2}\text{kg}$ sugar whereas Rohit bought $3\frac{1}{2}\text{kg}$ or sugar. Find the total amount of sugar bought by both of them.
→Simplify:$6\frac{1}{6}-5\frac{1}{5}+3\frac{1}{3}$
→Divide and check your answer by the corresponding multiplication in the following:
257796 ÷ 341
257796 ÷ 341
In the following numbers, replace * by the smallest number to make it divisible by 11:
39*43
39*43
Simplify:
a - [2b - {3a - (2b - 3c)}]
a - [2b - {3a - (2b - 3c)}]
The cost of a pen is $\text{Rs. }6\frac{2}{3}$ and that of a pencil is $\text{Rs. }4\frac{1}{6}.$ Which costs more and by how much?
→Find two numbers such that one of them exceeds the other by 18 and their sum is 92.