Question
Write the following relations as sets of ordered pairs and find which of them are functions:
$\big\{(\text{x},\text{y})=\text{x}+\text{y}=3,\text{x},\text{y}\in\{0,1,2,3\}\big\}$

Answer

We have,
$\big\{(\text{x},\text{y})=\text{x}+\text{y}=3,\text{x},\text{y}\in\{0,1,2,3\}\big\}$
Now, y = 3 - x
Putting x = 0, 1, 2, 3, we get
y = 3, 2, 1, 0 respectively
$\therefore$ R = {(0, 3), (1, 2), (2, 1), (3, 0)}
Yes, this relation is a function.

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