MCQ
Write the function in the simplest form: $\tan ^{-1}\left(\frac{1}{\sqrt{x^{2}-1}}\right),|x|>1$
  • $\frac{\pi}{2}-\sec ^{-1} x $
  • B
    $\frac{\pi}{2}+\sec ^{-1} x $
  • C
    $\frac{\pi}{2} + cosec ^{-1} x $
  • D
    $\frac{\pi}{2}-cosec ^{-1} x $

Answer

Correct option: A.
$\frac{\pi}{2}-\sec ^{-1} x $
a
$\tan ^{-1} \frac{1}{\sqrt{x^{2}-1}},|x|>1$

Put $x=cosec \theta \Rightarrow \theta=cosec^{-1} x$

$\therefore \tan ^{-1} \frac{1}{\sqrt{x^{2}-1}}$

$=\tan ^{-1} \frac{1}{\sqrt{\cos e c^{2} \theta-1}}$

$=\tan ^{-1}\left(\frac{1}{\cot \theta}\right)$

$=\tan ^{-1}(\tan \theta)$

$=\theta$

$=cosec ^{-1} x$

$=\frac{\pi}{2}-\sec ^{-1} x $    $\left[A s, \cos e c^{-1} x+\sec ^{-1} x=\frac{\pi}{2}\right]$

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