Question
Write the general solution of the equation $\frac{d y}{d x}+\frac{1}{x} y=$ $x$.

Answer

$P =\frac{1}{x}$
$\therefore$
$
\begin{aligned}
\text { I.F. } & =e^{\int P d x}=e^{\int \frac{1}{x} d x} \\
\text { I.F. } & =e^{\log x}=x \\
y . \text { I.F. } & =\int(\text { I.F. } \times \text { Q }) d x \\
y \times x & =\int x \times x d x=\int x^2 d x
\end{aligned}
$
$
\Rightarrow \quad x y=\frac{x^3}{3}+c
$

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