Question
Write the ions present in:
  1. $\ce{Al2(CO3)3}$
  2. $\ce{AlBr3}$

Answer

  1. $2$ ions of $\ce{Al^{3+}}$
$3$ ions of $\ce{CO3^{2-}}$
Hence total no. of ions $= 5$
  1. The ions present in $\ce{AlBr3}$ are aluminum ion $(\ce{Al^{3+}})$ and bromide ions $(\ce{Br^{1-}})$

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