Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsRotational Dynamics4 Marks
Question
Write the kinematical equations for circular motion in analogy with linear motion.
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Answer
For circular motion of a particle with constant angular acceleration $\alpha$, average angular speed, $\omega_{\mathrm{av}}=\frac{\omega_0+\omega}{2}$ $ \alpha=\frac{\omega-\omega_0}{t} \text { and } \begin{gathered} \\ \theta-\theta_0=\omega_{\text {av }} \cdot t \end{gathered} $ where $\omega_0$ and $\omega$ are the initial and final angular speeds, $t$ is the time, $\omega_{a v}$ the average angular speed and 00 and 0 the initial and final angular positions of the particle. Then, the angular kinematical equations for the circular motion are (in analogy with linear kinematical equations for constant linear acceleration) $ \begin{aligned} & \omega=\omega_0+\alpha t \\ & \theta-\theta_0=\omega_0 t+\frac{1}{2} \alpha t^2 \\ & \omega^2=\omega_0^2+2 \alpha\left(\theta-\theta_0\right) \end{aligned} $
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