Question
Write the maximum and minimum values of $\cos(\cos\text{x}).$
✓
Answer
$-1\le\cos(\text{x})\le1$ For $\text{x }\in [0, 2\pi]$
$\cos(\text{x})$ is maximum at x = 0 and minimum at $\text{x}=\pi.$
$\cos(\cos(0))=\cos(1)=0.9984$
$\cos(\cos(\pi))=\cos(-1)=\cos(1)$
$\cos\Big(\cos\Big(\frac{\pi}{2}\Big)\Big)=\cos(0)=1$
The maximum value of $\cos(\cos(\text{x}))$ is 1.
The manimum value of
$\cos(\cos(\text{x}))$ is $\cos(1).$
$\cos(\text{x})$ is maximum at x = 0 and minimum at $\text{x}=\pi.$
$\cos(\cos(0))=\cos(1)=0.9984$
$\cos(\cos(\pi))=\cos(-1)=\cos(1)$
$\cos\Big(\cos\Big(\frac{\pi}{2}\Big)\Big)=\cos(0)=1$
The maximum value of $\cos(\cos(\text{x}))$ is 1.
The manimum value of
$\cos(\cos(\text{x}))$ is $\cos(1).$
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