Question
Write the number of numbers that can be formed using all for digits $1, 2, 3, 4.$
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$\left(1+x^2\right)^{-1}$
$i^{403}$
$\frac{n}{6 !}=\frac{4}{8 !}+\frac{3}{6 !}$
| Elementary events: | $W1$ | $W2$ | $W3$ | $W_4$ | $W_5$ | $W_6$ | $W_7$ |
| $\frac{1}{7}$ | $\frac{1}{7}$ | $\frac{1}{7}$ | $\frac{1}{7}$ | $\frac{1}{7}$ | $\frac{1}{7}$ | $\frac{1}{7}$ |
A ∩ B

$\{x\}=0.5$
B – C