Question
Write the numerical coefficient term in the following algebraic expressions: $4\text{x}^2\text{y}-\frac32\text{xy}+\frac52\text{xy}^2$
✓
Answer
The numerical coefficient term in the given algebraic expression is as follows.
| Term | Coefficient |
| $\text{4x}^2\text{y}$ | $4$ |
| $-\frac32\text{xy}$ | $-\frac32$ |
| $\frac{5}{2}\text{xy}^2$ | $\frac52$ |
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Give four rational numbers equivalent to
$\frac{5}{-3}$
→$\frac{5}{-3}$
Multiply and reduce to lowest form and convert into a mixed fraction.
$20 \times \frac{4}{5}$
→$20 \times \frac{4}{5}$
Identify the terms and also mention the numerical coefficients of those terms:
$4 x y,-5 x^2 y,-3 y x, 2 x y^2$
→$4 x y,-5 x^2 y,-3 y x, 2 x y^2$
Give first the step you will use to separate the variable and then solve the equation.
$\frac{p}{7}=4$
→$\frac{p}{7}=4$
Write $‘T’$ for true and $‘F’$ for false for the following: If $8 : x :: 48 : 18,$ then $x = 3.$
→4b - 3
Write the following equations in statement form.
$\frac{p}{2}+2=8$
→$\frac{p}{2}+2=8$
Express $\frac{-3}{5}$ as a rational number with
numerator-18
→numerator-18
Evaluate the following:
25 ÷ 0.01 = 25 × _______
25 ÷ 0.01 = 25 × _______
In Figure.$AD \bot BC$ and $AD$ is the bisector of angle $BAC.$ Then, $\triangle\text{ABD} \cong\triangle\text{ACD}$ by $RHS.$
In $\triangle\text{ABD}$ and $\triangle\text{ACD},$
$\text{AD} = \text{AD}$ [common side] $\angle\text{BAD}=\angle\text{CAD}$
$[\because AD$ is the bisector of $\angle\text{BAC}]$ By $ASA$ congruence criterion, $\triangle\text{ABD}\cong\triangle\text{ACD}$
→In $\triangle\text{ABD}$ and $\triangle\text{ACD},$
$\text{AD} = \text{AD}$ [common side] $\angle\text{BAD}=\angle\text{CAD}$
$[\because AD$ is the bisector of $\angle\text{BAC}]$ By $ASA$ congruence criterion, $\triangle\text{ABD}\cong\triangle\text{ACD}$