Write the parametric equations of the circles: (x-3)^2+(y+4)^2=25 - Vidyadip

Question

Write the parametric equations of the circles:
$(x-3)^2+(y+4)^2=25$

✓

Answer

Given equation of the circle is
$(x-3)^2+(y+4)^2=25$
$\Rightarrow(x-3)^2+(y+4)^2=5^2$
Comparing this equation with $(x-h)^2+(y-k)^2=r^2$, we get
h = 3, k = -4 and r = 5
The parametric equations of the circle in terms of θ are
x = h + r cos θ and y = k + r sin θ
⇒ x = 3 + 5 cos θ and y = -4 + 5 sin θ

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