Write the structure of the major organic product in each of the following reaction:
$\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2+\text{HBr}\xrightarrow{\text{peroxide}}$
$\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2+\text{HBr}\xrightarrow{\text{peroxide}}$
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$\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2+\text{HBr}\xrightarrow[\text{Anti-Markovnikov's addition}]{\text{peroxide}}\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2-\text{SO}_2+\text{Br}\\ \ 1-\text{But-1-ene}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1-\text{Bromobutane} $
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