Question
Write the value of $1+i^2+i^4+\ldots\ldots +i^{2 n}.$

Answer

$\quad1+i^2+i^4+i^6+\ldots \ldots+i^{2 n}$
$=1-1+1-1+\ldots \ldots +(-1)^{2 n}$
Clearly the required value depends on the value of $n$.

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