Question
Write the value of $2(\sin^6\text{x}+\cos^6\text{x})-3(\sin^4\text{x}+\cos^4\text{x})+1.$

Answer

$2(\sin^6\theta+\cos^6\theta)-3(\sin^4\theta+\cos^4\theta)+1$
$=2((\sin^3\theta)^2)+(\cos^2\theta)^2)-3((\sin^2\theta)^2+(\cos^2\theta)^2)+1$
$=2(1)-3(1)+1$
$=2-3+1$
$=0$

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