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Inverse Trigonometric Functions — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsInverse Trigonometric Functions2 Marks
Question
Write the value of $\sin^{-1}\Big(\sin\frac{3\pi}{5}\Big)$
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Answer

$\sin^{-1}\Big(\sin\frac{3\pi}{5}\Big)=\sin^{-1}\Big[\sin\Big(\pi-\frac{2\pi}{5}\Big)\Big]$
$=\sin^{-1}\Big(\sin\frac{2\pi}{5}\Big)$
$=\frac{2\pi}{5}$

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