Question
$\text{x}\frac{\text{b}-\text{c}}{\text{b}\text{c}}\ \text{x}\frac{\text{c}-\text{a}}{\text{c}\text{a}}\text{x}\frac{\text{a}-\text{b}}{\text{a}\text{c}}=$
- aa+b+c
- xabc
- 1
- 0
Solution:
$\text{x}\frac{\text{b}-\text{c}}{\text{b}\text{c}}\text{x}\frac{\text{c}-\text{a}}{\text{ac}}\text{x}\frac{\text{a}-\text{b}}{\text{ac}}\text{x}\frac{\text{b}-\text{c}}{\text{bc}}+\frac{\text{c}-\text{a}}{\text{ca}}+\frac{\text{a}-\text{b}}{\text{ac}}$
$\text{x}^0=1$
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$x+y+z=5$ ; $x+2 y+3 z=\mu$ ; $x+3 y+\lambda z=1$
is constructed. If $\mathrm{p}$ is the probability that the system has a unique solution and $\mathrm{q}$ is the probability that the system has no solution, then :