MCQ
${x^2} = xy$ is a relation which is
  • A
    Symmetric
  • Reflexive
  • C
    Transitive
  • D
    None of these

Answer

Correct option: B.
Reflexive
b
(b) It is obvious.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The triangle formed by the points $(0, 7, 10), (-1, 6, 6), (-4, 9, 6)$ is
Let $C_i \equiv  x^2 + y^2 = i^2 (i = 1,2,3)$ are three circles. If there are $4i$ points on circumference of circle $C_i$. If no three of all the points on three circles are collinear then number of triangles which can be formed using these points whose circumcentre does not lie on origin, is-
The sum of the absolute maximum and absolute minimum values of the function $f(x)=\tan ^{-1}(\sin x-\cos x)$ in the interval $[0, \pi]$ is.
The area of smaller part between the circle ${x^2} + {y^2} = 4$ and the line $x = 1$ is
Let $f$ be any function continuous on $[\mathrm{a}, \mathrm{b}]$ and twice differentiable on $(a, b) .$ If for all $x \in(a, b)$ $f^{\prime}(\mathrm{x})>0$ and $f^{\prime \prime}(\mathrm{x})<0,$ then for any $\mathrm{c} \in(\mathrm{a}, \mathrm{b})$ $\frac{f(\mathrm{c})-f(\mathrm{a})}{f(\mathrm{b})-f(\mathrm{c})}$ is greater than
The point of intersection of the lines $\frac{{x - 5}}{3} = \frac{{y - 7}}{{ - 1}} = \frac{{z + 2}}{1},$ $\frac{{x + 3}}{{ - 36}} = \frac{{y - 3}}{2} = \frac{{z - 6}}{4}$ is
If $A = \left[ {\begin{array}{*{20}{c}}3&2\\1&4\end{array}} \right]$, then $A(adj\,A) = $
Let $\mathrm{p}$ and $\mathrm{q}$ be real numbers such that $\mathrm{p} \neq 0, \mathrm{p}^3 \neq \mathrm{q}$ and $\mathrm{p}^3 \neq-\mathrm{q}$. If $\alpha$ and $\beta$ are nonzero complex numbers satisfying $\alpha+\beta=-\mathrm{p}$ and $\alpha^3+\beta^3=\mathrm{q}$, then a quadratic equation having $\frac{\alpha}{\beta}$ and $\frac{\beta}{\alpha}$ as its roots is
Area bounded by the tangents of the curve given by $y = \sin \theta \,{\cos ^2}\theta $ ; $x = {\sin ^2}\theta \,\cos \theta $ which are parallel to co-ordinate axes (other than axes), is
$\int {\frac{{{3^x}}}{{\sqrt {{9^x} - 1} }}\,\,dx = } $