MCQ
$x^4+7 x^2+16$ can be factorised as :
- ✓$\left(x^2+x+4\right)\left(x^2-x+4\right)$
- B$\left(x^2+x-4\right)\left(x^2-x+4\right)$
- C$\left(x^2-x-4\right)\left(x^2+x+4\right)$
- Dnone of these
✓
Answer
Correct option: A.
$\left(x^2+x+4\right)\left(x^2-x+4\right)$
A
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A triangle and a parallelogram, both having base 5 cm , are situated between the same parallels. If the height of the triangle is 4 cm , then the area of the parallelogram is :
The solution of the simultaneous equations $\frac{x}{2}-\frac{y}{3}=0$ and $\frac{3 x}{2}+\frac{2 y}{3}+10=0$ is :
→Assertion (A) : In the figure, AB and AC are equal chords of a circle with centre $O$. If $O D=4 cm$, then OE is also 4 cm .
Reason (R): Equal chords of a circle are equidistant from the centre.
→Reason (R): Equal chords of a circle are equidistant from the centre.
The width of each class interval of a grouped frequency distribution is 8. The lower boundary of the class whose mid-value is 10 is:
$1-x^9=(1-x)\left(1+x+x^2\right)$ __________
→There is a road of equal width all around a circular garden. The outer and inner circumferences of the road are 328 m and 200 m respectively. The area of the road will be :
$\log _3\left(\frac{1}{27}\right)=$
→In the adjoining figure, $AB = AC , BD = CD$, $\angle BAD =32^{\circ}, \angle BDC =56^{\circ}, \angle CAD =2 x^{\circ}$ and $\angle BDA =(x+y)^{\circ}$. The values of $x$ and $y$ will be :
→BP and CQ are two medians of a $\triangle ABC$. If $QP =4 cm$, then $BC =$
→Assertion (A): The present population of a town decreases at the rate of 5% p.a. due to migration. Its present population is 21600 and 2 years ago it was 24000.
Reason (R): Let there be an increase in population at R% p.a. Then population after n years is given by $P \left(1-\frac{ R }{100}\right)^n$, where P is the present population.
→Reason (R): Let there be an increase in population at R% p.a. Then population after n years is given by $P \left(1-\frac{ R }{100}\right)^n$, where P is the present population.