x^5 + 10 x^4 a + 40 x^3 a^2 + 80 x^2 a^3 + 80x a^4 + 32 a^5 = - Vidyadip

MCQ

${x^5} + 10{x^4}a + 40{x^3}{a^2} + 80{x^2}{a^3}$$ + 80x{a^4} + 32{a^5} = $

A
${(x + a)^5}$
B
${(3x + a)^5}$
✓
${(x + 2a)^5}$
D
${(x + 2a)^3}$

✓

Answer

Correct option: C.

${(x + 2a)^5}$

c
(c) Conversely,${(x + a)^n} = {\,^n}{C_0} + {\,^n}{C_1}{x^{n - 1}}a + {\,^n}{C_2}{x^{n - 2}}{a^2} + .....$

So, ${(x + 2a)^5} = {x^5} + 10{x^4}a + 40{x^3}{a^2} + 80{x^2}{a^3} + 80x{a^4} + 32{a^5}$.

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