MCQ
${x^5} + 10{x^4}a + 40{x^3}{a^2} + 80{x^2}{a^3}$$ + 80x{a^4} + 32{a^5} = $
- A${(x + a)^5}$
- B${(3x + a)^5}$
- ✓${(x + 2a)^5}$
- D${(x + 2a)^3}$
✓
Answer
Correct option: C.
${(x + 2a)^5}$
c
(c) Conversely,${(x + a)^n} = {\,^n}{C_0} + {\,^n}{C_1}{x^{n - 1}}a + {\,^n}{C_2}{x^{n - 2}}{a^2} + .....$
(c) Conversely,${(x + a)^n} = {\,^n}{C_0} + {\,^n}{C_1}{x^{n - 1}}a + {\,^n}{C_2}{x^{n - 2}}{a^2} + .....$
So, ${(x + 2a)^5} = {x^5} + 10{x^4}a + 40{x^3}{a^2} + 80{x^2}{a^3} + 80x{a^4} + 32{a^5}$.
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