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STD 11 - basic of algoritham — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - basic of algoritham4 Marks
MCQ
${({x^5})^{1/3}}{(16{x^3})^{2/3}}$${\left( {{1 \over 4}{x^{4/9}}} \right)^{ - 3/2}} = $
  • A
    ${(x/4)^3}$
  • B
    ${(4x)^3}$
  • C
    $8{x^3}$
  • ✓
    None of these
✓

Answer

Correct option: D.
None of these
d
(d) ${({x^5})^{1/3}}{(16{x^3})^{2/3}}{\left( {{1 \over 4}{x^{4/9}}} \right)^{ - 3/2}}{x^{{5 \over 3} + 3\,.\,{2 \over 3}\, - \,{4 \over 9}.{3 \over 2}}}{2^{{2 \over 3}\,.\,4 + 3}} $

$= {2^{{{17} \over 3}}}{x^3}$.

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