MCQ
$XeF_2$ reacts with $PF_5$ to give
- A$XeF_6$
- ✓$[XeF]^+ [PF_6]^-$
- C$XeF_4$
- D$[PF_4]^+ [XeF_3]^-$
✓
Answer
Correct option: B.
$[XeF]^+ [PF_6]^-$
b
$PF _5$ is a fluoride ion acceptor so it yields cationic species with xenon fluorides.
$PF _5$ is a fluoride ion acceptor so it yields cationic species with xenon fluorides.
$\left[ XeF _2\right]+\left[ PF _5\right] \rightarrow[ XeF ]^{+}\left[ PF _6\right]^{-}$
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