MCQ
$Xe{F_4}$ on partial hydrolysis produces
- A$Xe{F_2}$
- ✓$XeO{F_2}$
- C$XeO{F_4}$
- D$Xe{O_3}$
✓
Answer
Correct option: B.
$XeO{F_2}$
b
(b) Partial hydrolysis; $Xe{F_4} + {H_2}O \to $$XeO{F_2} + 2HF$
(b) Partial hydrolysis; $Xe{F_4} + {H_2}O \to $$XeO{F_2} + 2HF$
Complete hydrolysis;
$2Xe{F_4} + 3{H_2}O\, \to $$Xe + Xe{O_3} + {F_2} + 6HF$
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