MCQ
$Xe{F_4}$ on partial hydrolysis produces
- A$Xe{F_2}$
- ✓$XeO{F_2}$
- C$XeO{F_4}$
- D$Xe{O_3}$
Complete hydrolysis;
$2Xe{F_4} + 3{H_2}O\, \to $$Xe + Xe{O_3} + {F_2} + 6HF$
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$A.$ $\left[ Fe ( CN )_6\right]^{3-}$;$B.$ $\left[ FeF _6\right]^{3-}$; $C.$ $\left[ CoF _6\right]^{3-}$; $D.$ $\left[ Cr (\text { oxalate })_3\right]^{3-}$; $E.$ $\left[ Ni ( CO )_4\right]$
Choose the correct answer from the options given below:
$STATEMENT-2$: Both geometrical isomers of the complex $\left[\mathrm{M}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]$ possess axis of symmetry.
Reason : $sp$ hybridised carbon atoms of acetylene are considerably electronegative.