MCQ
$Xe{F_6}$ on hydrolysis gives
- ✓$Xe{O_3}$
- B$XeO$
- C$Xe{O_2}$
- D$Xe$
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Above conversion can be achieved by
$A(g)\,\xrightarrow{{{K_1}\, = \,2\, \times \,{{10}^{ - 3}}\,\,{S^{ - 1}}}}2B\,(g)$
$A(g)\,\xrightarrow{{{K_2}\, = \,1\, \times \,{{10}^{ - 3}}\,\,{S^{ - 1}}}}C\,(g)$