MCQ
$XeF_6$ on partial hydrolysis with water produces a compound $'X'$. The same compound $'X'$ is formed when $XeF_6$ reacts with silica. The compound $'X'$ is
- A$XeF_2$
- B$XeF_4$
- ✓$XeOF_4$
- D$XeO_3$
$Xe{F_6} + 2{H_2}O\, \to Xe{O_2}{F_2}+ \,4HF$
$Si{O_2}\, + \,2Xe{F_6}\, \to \mathop {\,2XeO{F_4}\, + \,Si{F_4}}\limits_{(Xenoneoxy\,\,\,tetra\,\,fluoride)} $
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$KOH + {O_3} \to coloured\,solid\,(a) + Gas\,(b) + {H_2}O$
Select $CORRECT$ statement
| List $I$ | List $II$ | ||
| $A$ | $\alpha$-Glucose and $\alpha-$Galactose | $I$ | Functional isomers |
| $B$ | $\alpha$-Glucose and $\beta-$-Galactose | $II$ | Homologous |
| $C$ | $\alpha$-Glucose and $\alpha$-Galactose | $III$ | Anomers |
| $D$ | $\alpha$-Glucose and $\alpha$-Galactose | $IV$ | Epimers |
Choose the correct answer from the options given below:
