Question
$x^m+x^m=x^{2 m}$, where $x$ is a non-zero rational number and $m$ is a positive integer

Answer

$a^m \times a^n=a^{m+n}$
$x^m \times x^m=x^{m+m}=x^{2 m}$
$\text { Also, } a^k+a^k=2 a^k$
$\text { So, } x^m+x^m=2 x^m$

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