Question
$x^m+x^m=x^{2 m}$, where $x$ is a non-zero rational number and $m$ is a positive integer.

Answer

$x^{m!}+x^m=x^{2 m} \quad$ (False)
Correct : As $x^m+x^m=2 \times x^m$ and $x^{2 m}=\left(x^2\right)^m$

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