Question
यदि $ - 1 + \sqrt { - 3} = r{e^{i\theta }},$तो $\theta $ बराबर है
$ = r\cos \theta + ir\sin \theta $
वास्तविक एवं काल्पनिक भागों की तुलना करने पर,
$r\cos \theta = - 1$एवं $r\sin \theta = \sqrt 3 $
अत:$\tan \theta = - \sqrt 3 \,\, \Rightarrow \tan \theta = \tan \frac{{2\pi }}{3}$. अत: $\theta = \frac{{2\pi }}{3}$.
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