MCQ
यदि $3 x+2 y=\sin x$ तो $\frac{d y}{d x}$ है-
  • A
    $\frac{\cos x+3}{2}$
  • B
    $\frac{\cos x-2}{3}$
  • $\frac{\cos x-3}{2}$
  • D
    $\frac{\cos x+2}{3}$

Answer

Correct option: C.
$\frac{\cos x-3}{2}$
(C) $\frac{\cos x-3}{2}$
$\begin{aligned} \frac{d}{d x}(3 x+2 y) & =\frac{d}{d x}(\sin x) \\ \Rightarrow \quad 3+2 \frac{d y}{d x} & =\cos x \\ \Rightarrow \quad \frac{d y}{d x} & =\frac{\cos x-3}{2}\end{aligned}$

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