Question
यदि $3f(x) - 2f(1/x) = x,$ तो $f'(2) = $
माना $\frac{1}{x} = y$, तब $3f(1/y) - 2f(y) = 1/y$
==> $ - 2f(y) + 3f\left( {\frac{1}{y}} \right) = \frac{1}{y}$
==>$ - 2f(x) + 3f\left( {\frac{1}{x}} \right) = \frac{1}{x}$ .....$(ii)$
समी. $(i)$ में $3$ से तथा समी. $(ii)$ में $2$ से गुणा करके जोड़ने पर,
$9f(x) - 6f(1/x) - 4f(x) + 6f(1/x) = 3x + (2/x)$
$5f(x) = 3x + 2/x$
==> $f(x) = 1/5\,\left[ {3x + 2/x} \right]$
==> $f'(x) = \frac{1}{5}\left[ {3 - \frac{2}{{{x^2}}}} \right]$
==> $f'(2) = \frac{1}{5}\left[ {3 - \frac{2}{4}} \right] = \frac{1}{2}$.
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