MCQ
यदि A और B दो स्वतंत्र घटनाएँ हों तो
  • $P(A \cup B)=1-P\left(A^{\prime}\right) P\left(B^{\prime}\right)$
  • B
    $P(A \cap B)=1-P\left(A^{\prime}\right) P\left(B^{\prime}\right)$
  • C
    $P(A \cup B)=1+P\left(A^{\prime}\right) P\left(B^{\prime}\right)$
  • D
    $P(A \cup B)=\frac{P\left(A^{\prime}\right)}{P\left(B^{\prime}\right)}$

Answer

Correct option: A.
$P(A \cup B)=1-P\left(A^{\prime}\right) P\left(B^{\prime}\right)$
A

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