MCQ
यदि A और B दो स्वतंत्र घटनाएँ हों तो
- ✓$P(A \cup B)=1-P\left(A^{\prime}\right) P\left(B^{\prime}\right)$
- B$P(A \cap B)=1-P\left(A^{\prime}\right) P\left(B^{\prime}\right)$
- C$P(A \cup B)=1+P\left(A^{\prime}\right) P\left(B^{\prime}\right)$
- D$P(A \cup B)=\frac{P\left(A^{\prime}\right)}{P\left(B^{\prime}\right)}$