Question
यदि $\cos (A - B) = \frac{3}{5}$ तथा $\tan A\tan B = 2,$ तब
$\therefore $ $5\,\,\cos A\,\,\cos B + 5\,\,\sin A\,\,\sin B = 3$…..$(i)$
द्वितीय सम्बन्ध से, $\sin A\sin B = 2\cos A\cos B$.....$(ii)$
$\therefore $ $\cos A\cos B = \frac{1}{5}$
एवं $5\,\left( {\frac{1}{2} + 1} \right)\,\sin A\,\,\sin B = 3$.
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