Question
यदि $\cos (x + y) = y\sin x,$ तो $\frac{{dy}}{{dx}} = $
==> $ - \sin (x + y)\left( {1 + \frac{{dy}}{{dx}}} \right) = y\cos x + \sin x\frac{{dy}}{{dx}}$
==> $\frac{{dy}}{{dx}} = - \frac{{y\cos x + \sin (x + y)}}{{\sin (x + y) + \sin x}}$.
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